Let \(\mathbb R\) be with the usual standard topology and let A \subsets \mathbb R\).Then A is open in \(\mathbb R\) if there exists an interval I such that I\subset A. For a,b\(\epsilon\mathbb R, I =
—>> I = ( a, b)
I = ( a, b]
I = [ a,b]
I = [a,b)
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Let \(\mathbb R\) be with the usual standard topology and let A \subsets \mathbb R\).Then A is open in \(\mathbb R\) if there exists an interval I such that I\subset A. For a,b\(\epsilon\mathbb R, I =
—>> I = ( a, b)
I = ( a, b]
I = [ a,b]
I = [a,b)