Write the equation of this ellipse \( 25x^2+4y^2-50x-16y-59=0\) in the canonical form.
\(\frac{(x-1)^2}{4}+\frac{(y+2)^2}{25}=1\)
\(\frac{(x+1)^2}{4}+\frac{(y-2)^2}{25}=1\)
\(\frac{(x-1)^2}{4}-\frac{(y-2)^2}{25}=1\)
—>> \(\frac{(x-1)^2}{4}+\frac{(y-2)^2}{25}=1\)