MTH282 Tma Solutions

MTH282

Question: Find the magnitude of this this vector \\(a=-i+2j+2k\\)
Answer: 3

Question: Calculate the Jacobian determinant of \\(T(u,v)=(uA2-v>uA2+v)\\). Find the magnitude of the acceleration at any time \\(t\\).
Answer: 4u

Question: If \\(A=3i-j-4k\\), \\(B=-2i+4j and \\(C=i+2j-k\\), find \\(|A+B+C|\\)
Answer: W(â’s93\\)

Question: If \\(î>(xly,z)=3xA2 y-yA3 zA2\\),find \\(â“4:î,\\) (grad ÎJ at the point (1, -2, -1).
Answer: \\(-12i-9j-16k\\)

Question: Find the work done in moving an object along a straight line from (3, 2, -1) to (2, -1,4) in a force field given by \\(F=4i- 3j+2k\\)
Answer: 15J

Question: Find the angle between \\(A=2i+2j- k\\) and \\(B=6i-3j+2k\\) to nearest whole number.
Answer: \\(79^o\\)

Question: Find the resultant of these vectors \\(a=2i+4j-5k\\) and \\(b=i+2j+3k\\)
Answer: \\(3i+6j-2k\\)

Question: Determine the \\(curl R\) at the point (2, 0, 3) given that \\(F=xz i+(2xA2-y)j- yzA2 k\\).
Answer: \\(-9i+8k\\)

Question: Find the directional derivative of \\ (|.=xyA2+yzA2+xyz\\) at the point (2, -1,1) in the direction of the vector \\(A=2i+4j-k\\).
Answer: \\(-\\frac{4}{21}â“s21\\)

Question: Find the directional derivative of \\ (|.=xyA2+yzA2+xyz\\) at the point (2, -1,1) in the direction of the vector \\(A=2i+4j-k\\).
Answer: \\(-\\frac{4}{21}â“s21\\)

Question: Given that \\(R=sinâDit i+cosâD jt j+tk\\), find \\( (dA2 R)/(dtA2 )\\).
Answer: [B] W(-sinâDj t i-cosâDj t j\\)

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