A spring of natural length 1.5 cm is extended 0.0050 m by a force of 0.8N.What will its length be when the applied force is 3.5 N?
Answer: 1.52 m
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A spring of natural length 1.5 cm is extended 0.0050 m by a force of 0.8N.What will its length be when the applied force is 3.5 N?
Answer: 1.52 m
JOIN OUR NOUN TELEGRAM GROUP HERE FOR MORE – ONLINE TUTORIAL ALSO AVAILABLE