If \(y=x^3-x^2-x+6\), find the values of \( x\) at the turning points.
—>> 1 and \(frac{-1}{3}\)
\(\frac{1}{3}\)
\(-1\) and \(\frac{-1}{3}\)
\(1\) and \(\frac{1}{3}\)
Tutors, Past Questions and Projects.
If \(y=x^3-x^2-x+6\), find the values of \( x\) at the turning points.
—>> 1 and \(frac{-1}{3}\)
\(\frac{1}{3}\)
\(-1\) and \(\frac{-1}{3}\)
\(1\) and \(\frac{1}{3}\)
