by: Admin_LouisPosted on: Find the gradient of the curve with equation \(2x^2-4xy+3y^2 = 3\) at the point (2,1). Find the gradient of the curve with equation \(2x^2-4xy+3y^2 = 3\) at the point (2,1).431—>> 2 Share this:TwitterFacebookLike this:Like Loading... Related posts:The distance s in meters covered by a particle in \(t\) seconds is \(s=\frac{3}{2} t^2-3t\). Find its acceleration.What is the derivative of \(\sqrt {x}\)If \(y=x^3-x^2-x+6\), find the values of \( x\) at the turning points.Evaluate the integral \(\int_{2}^{4} (x^{2}-1) dx\)