A 10μC charge moves with a velocity of 1.0×105ms−1 at right angle to a uniform magnetic field of flux density 5.0×10−4T. Calculate the force on the charge.

A 10μC charge moves with a velocity of 1.0×105ms−1 at right angle to a uniform magnetic field of flux density 5.0×10−4T. Calculate the force on the charge.

 

Options

A) 5.0×10−5N5.0×10−5N

B)5.0×10−4N5.0×10−4N >>>>>>>>>>

C)5.0×105N5.0×105N

D)5.0×106N

…………………………………………………………………………………………………………………………….

Explanation:

F=qvB

=10×10−6×1.0×105×10−4

=5.0×10−4N

……………………………………………………………………………………………………………………………………

We have WAEC, GCE, NECO, JAMB ONLINE TUTORIAL CLASS that can help you out. CLICK HERE TO GET STARTED.

 

Leave a Reply

MEET OVER 2000 NOUN STUDENTS HERE. 

Join us for latest NOUN UPDATES and Free TMA answers posted by students on our Telegram. 

OUR ONLINE TUTORIAL CLASS IS NOW ON!!! JOIN US NOW. 
JOIN NOW!
close-link
%d bloggers like this: