MTH312 Solutions

MTH312 Tma Solutions

1. A ring that is commutative ring and has a multiplicative ring with unity is called

a kernel commutative ring

an identity commutative ring with euclidean property

a unique commutative ring with one element

—>> a commutative ring with unity

2. A subgroup \(H\) of a group \(G\) is normal if

\(Hx=xH\) for some \(x\in G\)

\(Hx\neq xH\) for all \(x\in G\)

—>> \(H/xH\) for some \(x\in G\)

\(Hx=G\) for all \(x\in G\)

3. Let \(R\) be a ring and \(I_R\) be the identity map then \(ker I_R\) is

\(R\)

—>> \({0}\)

\frac{R}{I_R}

empty

4. Given groups \(G\) and \(G^{\ast}\), a homomorphism \(\theta : G \rightarrow G^{\ast}\) is called an isomorphism if

\(\theta\) is surjective and inclusive

—>> \(\theta\) is injective and surjective

\(\theta\) is normal in \(G\)

\(\theta\) is inclusive and injective

5. The following product of cycles are the same except

\((1 3 2 4)\)

\((4 1 3 2)\)

\((2 4 1 3)\)

—>> \((1 2 3 4)\)

6. Given that \(A\) and \(B\) are cyclic groups of order \(m\) and \(n\) respectively, then \(A\times B\) is a

a normal subgroup of oder \(\frac{m}{n}\)

a permutation group of oder \(m+n\)

—>> a cyclic group of oder \(mn\)

a Cayley’s subgroup of oder \(m-n\)

7. If \(H\) and \(K\) are subgroups of a group \(G\) with \(K\) normal in \(G\), then

—>> \(H/(H\cap K)\)\cong (HK)/K\)

\(H/(H\cap K)\)\cong K/(HK)\)

\(H/(H\cap K)\)\cong H\cap K)/K\)

\(H/(H\cap K)\)\cong K/H\cap K\)

8. The index of a normal subgroup of a group \(G\) is

1

—>> 2

3

\(0\)

9. Given a permutation \(g=\left(\begin{array}{ccccc}1&2&3&4&5\\3&5&4&1&2\end{array}\right)\), then

—>> \(g=(1 3 4)(2 5)\)

\(g=(1 4 2)(3 5)\)

\(g=(1 2 3 4 5)\)

\(g=(1 3 4 2)\)

10. \(Im(sign)=\)

—>> \({1, -1}\)

\({1}\)

\({-1}\)

\({0,1}\)

JOIN OUR TELEGRAM ON VIP NOUN UPDATES – FOR FREE MTH312 PAST QUESTIONS AND EXAMS SUMMARIES

Leave a Reply

MEET OVER 2000 NOUN STUDENTS HERE. 

Join us for latest NOUN UPDATES and Free TMA answers posted by students on our Telegram. 

OUR ONLINE TUTORIAL CLASS IS NOW ON!!! JOIN US NOW. 
JOIN NOW!
close-link
%d bloggers like this: